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CBSE Class 11-science Answered

For decolourization of one mole of KMnO4, the required litre of 30 volume H2O2 in acidified medium?
1. 0.94
2. 9.4
3. 0.094
4. 3.01
Asked by Mamali Nanda | 15 Jul, 2016, 10:15: PM
answered-by-expert Expert Answer
1 mole of KMnO4 requires 2.5 moles of H2O2 for decolourisation. 
1 mole H2O2 = 34 g
Hence 2.5 moles H2O2 = 85 g
Also,
2H2O2 → 2H2O + O2
From the above equation,
2x34 g of H2O2 gives 22.4 L O2
Hence 30 L O2 can be obtained from = 30x2x34/22.4 = 91.07 g H2O2
1 L of 30 volumes of H2O2 contains 91.07 g H2O2
So, 85 g H2O2 corresponds to 0.933 L H2O2
Hence, correct ans is 0.94 (option 1)
Answered by Prachi Sawant | 17 Jul, 2016, 12:17: AM
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