For complete reaction of 50 g CaCO3. How many grams of 20% HCL is required
Asked by jgjaigupta1998 | 15th Apr, 2014, 10:36: AM
Expert Answer:
CaCO3 + 2HCL → CaCl2 + CO2 + H2O
1 mol 2 moles
20 % HCl contains 20 g HCl in 100 g water
1 mol CaCO3 = 100 g
50 g CaCO3 = 0.5 moles CaCO3
0.5 mole CaCO3 correspond to 1 mol HCl
1 mol HCl = 36.5 g HCl
20 g HCl in 100 g water
36.5 g HCl = 182.5 g H2O
Hence, 182.5 g solution of 20 % HCl is required.
CaCO3 + 2HCL → CaCl2 + CO2 + H2O
1 mol 2 moles
20 % HCl contains 20 g HCl in 100 g water
1 mol CaCO3 = 100 g
50 g CaCO3 = 0.5 moles CaCO3
0.5 mole CaCO3 correspond to 1 mol HCl
1 mol HCl = 36.5 g HCl
20 g HCl in 100 g water
36.5 g HCl = 182.5 g H2O
Hence, 182.5 g solution of 20 % HCl is required.
Answered by | 15th Apr, 2014, 01:15: PM
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