⭕ For a reaction 2H2O22H2O + O2 if rate of formation of O2 is 3.2×10^-3 kg/min then what will be rate of disappearance of h2O2 1)in mol/min  2)in g/sec  3)in kg/min

 

 

Asked by jhajuhi19 | 2nd Aug, 2021, 02:04: PM

Expert Answer:

For the given chemical reaction,
 
2 straight H subscript 2 straight O subscript 2 space space rightwards arrow 2 straight H subscript 2 straight O space plus thin space straight O subscript 2

minus 1 half fraction numerator straight d left square bracket straight H subscript 2 straight O subscript 2 right square bracket over denominator dt end fraction equals negative 1 half fraction numerator straight d left square bracket straight H subscript 2 straight O right square bracket over denominator dt end fraction equals fraction numerator straight d left square bracket straight O subscript 2 right square bracket over denominator dt end fraction

fraction numerator straight d left square bracket straight H subscript 2 straight O right square bracket over denominator dt end fraction equals 2 fraction numerator straight d left square bracket straight O subscript 2 right square bracket over denominator dt end fraction equals 2 cross times 3.6 space Mol space L to the power of negative 1 end exponent space min to the power of negative 1 end exponent

fraction numerator straight d left square bracket straight H subscript 2 straight O right square bracket over denominator dt end fraction equals 7.2 space straight M space min to the power of negative 1 end exponent

Rate space of space disappearance space of space straight H subscript 2 straight O subscript 2 comma space

minus fraction numerator straight d left square bracket straight H subscript 2 straight O subscript 2 right square bracket over denominator dt end fraction equals fraction numerator straight d left square bracket straight H subscript 2 straight O right square bracket over denominator dt end fraction equals negative fraction numerator straight d left square bracket straight H subscript 2 straight O right square bracket over denominator dt end fraction equals 7.2 space Mol space straight L to the power of negative 1 end exponent space min to the power of negative 1 end exponent

F o r space V o l u m e equals 1 space L

R a t e space o f space d i s a p p e a r a n c e space c a n space b e space c a l c u l a t e d space I n space g divided by s e c

g equals m o l e s cross times m o l a r space m a s s
M a s s space i n space g equals 7.2 cross times 18 equals 129.6 space g
m i n space i n space s e c equals 60 space s e c
S o comma space R a t e space o f space d i s a p p e a r a n c e space o f space H subscript 2 O subscript 2 equals 7.2 cross times fraction numerator 129.6 over denominator 60 end fraction
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 7.2 cross times 2.16
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 15.552 space straight g divided by sec
Rate space of space disappearance space of space straight H subscript 2 straight O subscript 2 space in space Kg divided by min
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 15.552 cross times 60 over 1000 equals 0.93312 space Kg divided by min

Answered by Ravi | 2nd Aug, 2021, 06:22: PM

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