CBSE Class 12-science Answered
flux through a gaussian surface which has enclosed a dipole ??
Asked by kothari_prachi | 25 May, 2010, 11:12: AM
Expert Answer
Dear student,
We have an electric dipole. draw a Gaussian surface around our electric dipole. Now, the total charge enclosed by our Gaussian surface is zero, so according the Gauss' Law the flux through the Gaussian surface is zero, and so is the electric field intensity due the electric dipole.
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Answered by | 25 May, 2010, 11:26: AM
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