Five years hence,the age of jacob will be three times that of his son. Five years ago,Jacob's age was seven times of his son .What are their present ages(solve point by point)
Asked by rs1947093 | 23rd Mar, 2020, 07:27: AM
Expert Answer:
According to the conditions, we get
y + 5 = 3(x + 5)
→ 3x - y = -10 .... (1)
y - 5 = 7(x - 5)
7x - y = 30 .... (2)
Subtracting (1) from (2), we get
4x = 40 → x = 10
Substitute the value of x in (1), we get
y = 3(10) + 10 = 40
Therefore, the present age of Jacob is 40 years and the present age of his Son is 10 years.
According to the conditions, we get
y + 5 = 3(x + 5)
→ 3x - y = -10 .... (1)
y - 5 = 7(x - 5)
7x - y = 30 .... (2)
Subtracting (1) from (2), we get
4x = 40 → x = 10
Substitute the value of x in (1), we get
y = 3(10) + 10 = 40
Therefore, the present age of Jacob is 40 years and the present age of his Son is 10 years.
Answered by Yasmeen Khan | 23rd Mar, 2020, 09:36: AM
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