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Five years ago , fathers age was 2 times the sum of ages of his three children. after 5 years fathers age can be obtained by subtracting 8 from the sum of ages of the three children. fathers present age is?
Asked by drpatilsm | 14 May, 2019, 10:19: PM

Let the present age of father be x years and sum of ages of his three children be y years.

Five years ago , fathers age was 2 times the sum of ages of his three children.

→  (x - 5) = 2(y - 15)
→   x - 2y= - 25   ... (i)

After 5 years fathers age can be obtained by subtracting 8 from the sum of ages of the three children.

→  (x + 5) = (y +15 - 8)
→         x - y   =  2   ... (ii)

Subtracting (ii) from (i), we get
y = 27

Put y = 27 in (ii), we get

x = 29

Therefore the present age of father is 29 years.
Answered by Yasmeen Khan | 15 May, 2019, 09:13: AM

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