Finding coordinates of one point of an equilateral triangle when other 2 points are given.

Asked by Janani Krishnan | 2nd Dec, 2010, 07:10: PM

Expert Answer:

Dear Student
 
Let A(3,4) and B (-2,3) be the two given vertices and (x,y) be the third vertex
So
AC =BC =AB
 
or AC2=BC2=AB2
 
 (x-3)2 + (y-4)2 = (x+2)2+(y-3)2 = 26
AC2 =BC2 gives
y =6-5x
Use this in
BC2= AB2
to get
x2+4x+4+9+25x2-30x=26
or 26 x2-26x-13=0
or 2x2-2x-1=0
so x =
Now find y = 6-5( )= 

Answered by  | 6th Dec, 2010, 11:02: AM

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