CBSE Class 11-science Answered
FIND
Asked by | 07 Sep, 2008, 10:06: AM
Expert Answer
Let the maximum force, which the man can exert be F acting at an angle θ. Now, breaking the rectangular components of 'F' along the horizontal and vertical direction:
(i) F cos θ in horizontal direction
(ii) F sin θ in vertical directioon.
Also, the weight of the body mg acts in vertically downward direction,
So, F sin θ + R = mg
or, R = mg - F sin θ.
The force of limiting friction, f = μ R = μ ( mg - F sin θ )
Now as long as 'F cosθ' is less than 'f' , acceleration is zero; which means the maximum force the man can exert
F cosθ < μ ( mg - F sin θ )
or,
Fmax < [μ ( mg - F sin θ )] / cos θ
Answered by | 12 Dec, 2008, 11:59: PM
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