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Asked by shekhar14351 | 18th Feb, 2010, 12:17: PM

Expert Answer:

Dear Student

Volume of the required copper V= 0.001X 10= 0.01 cc

Wt of required copper= 0.01 X9 =0.09 gm

Requred charge Q= cu wt /electro-chemical equivalent =  0.09 /(3/10000 )=299.7Columbs

Volt = joul/colubm

Work done = QX Voltage= 299.7X12=3600 J

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Answered by  | 1st Mar, 2010, 04:29: PM

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