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Asked by shekhar14351 | 18th Feb, 2010, 12:17: PM
Expert Answer:
Dear Student
Volume of the required copper V= 0.001X 10= 0.01 cc
Wt of required copper= 0.01 X9 =0.09 gm
Requred charge Q= cu wt /electro-chemical equivalent = 0.09 /(3/10000 )=299.7Columbs
Volt = joul/colubm
Work done = QX Voltage= 299.7X12=3600 J
Regards
Team
Topperlearning.com
Answered by | 1st Mar, 2010, 04:29: PM
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