Asked by | 16th Feb, 2009, 06:04: PM
Charge Q will be same on both the capacitors that are in series.
For capacitor A
Q = C1(40V )
For capacitor B
Q = C2(60V)
So C1/C2 = 3/2
C1 = 3x and C2 = 2x
On connecting 6 microfarad with B the potential drop is equal to that across A, so the capacitance of this combination is equal to the capacitance of A.
Now you can write an equation in variable x and solve it to find C1 and C2.
Answered by | 17th Feb, 2009, 03:38: PM
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