Asked by | 22nd Sep, 2008, 07:43: PM
B2-4AC = ( 11(a+b+c) )2 - 4* 2(a-b)*(-3)(a-b) =121(a+b+c)2 + 24 (a-b)2
here we can see that B2-4AC>0 since both the terms are square terms.
so roots of this equations are real and unequal since B2-4AC is not a perfect square.
Answered by | 15th Dec, 2008, 02:51: AM
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