CBSE Class 11-science Answered
FIND
Asked by | 24 Jun, 2008, 07:19: PM
Expert Answer
let y=sin(θ+π/6) + cos(θ+π/6)
differentiating w.r.t. θ
dy/dθ = cos(θ+π/6) - sin(θ+π/6)
for maxima dy/dθ = 0
i.e. tan(θ+π/6) = 1 => θ+π/6 = π/4 i.e. θ=π/12
so at θ=π/12 value of ymax = sin(π/12+π/6) + cos(π/12+π/6) = 21/2
Answered by | 12 Sep, 2008, 12:52: AM
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