Asked by | 23rd Sep, 2008, 10:21: PM
the first such no. is 1 and after that 5 and 9 and so on.
the last two digit no. will be 97.
so we have an A.P. with first term a=1 and last term l=97 and common difference d=4.
we have to find the sum of all terms of this A.P.
let us find out no. of terms in this A.P.
let no. of terms be n
then 97 = 1+(n-1)4 ==> n =25
sum of this A.P. = n/2(a+l) = 25/2(1+97) = 1225
Answered by | 24th Sep, 2008, 12:24: AM
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