CBSE Class 9 Answered
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Asked by fathima12 | 08 Dec, 2009, 07:32: PM
Expert Answer
x3+ 1/x3 = (x6 + 1)/x3
x3 = (2 - 1)3 = 22 - 32(2 - 1) - 1 = 22 - 6 + 32 - 1 = 52 -7
x6 = (x3)2 = (52 -7)2 = 50 - 702 + 49 = 99 - 702
(x6 + 1)/x3 = (99 - 702 + 1)/(52 -7) = (100 - 702)/(52 -7)
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Answered by | 09 Dec, 2009, 11:53: AM
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