Find zeroes of the polynomial
Asked by SHAMLI RAUT
| 10th Jun, 2013,
07:33: PM
Expert Answer:
f(x)=6x2-3 = 3(2x2-1)
Zeroes are 1/roo2, -1/root 2
Sum of zeroes = 1/roo2 -1/root 2 = 0 = -coefficient of x/coefficient of x2
Product of zeroes = (1/roo2) (-1/root 2) = -1/2 = -3/6 = constant term/coefficient of x2
This verifies the relationship between the zeroes and the coefficients of the given polynomial.
Answered by
| 10th Jun, 2013,
10:08: PM
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