Find zeroes of the polynomial

Asked by SHAMLI RAUT | 10th Jun, 2013, 07:33: PM

Expert Answer:

f(x)=6x2-3 = 3(2x2-1)
Zeroes are 1/roo2, -1/root 2
 
Sum of zeroes = 1/roo2 -1/root 2 = 0 = -coefficient of x/coefficient of x2
Product of zeroes = (1/roo2) (-1/root 2) = -1/2 = -3/6 = constant term/coefficient of x2
 
This verifies the relationship between the zeroes and the coefficients of the given polynomial.

Answered by  | 10th Jun, 2013, 10:08: PM

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