Find zero of quadratic polynomial

Asked by SHAMLI RAUT | 10th Jun, 2013, 07:29: PM

Expert Answer:

x2+7x+12
x2+4x+3x+12
= x(x+4)+3(x+4)
= (x+4)(x+3)
 
Zeroes are -4 and -3.
Sum of zeroes = -4-3 = -7 = - coefficient of x/ coefficient of x2
Product of zeroes = (-4)(-3) = 12 = constant term/ coefficient of x2
Hence,  the relationship between zeroes and the coefficients of the given polynomial is verified.

Answered by  | 10th Jun, 2013, 10:04: PM

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