Find zero of quadratic polynomial
Asked by SHAMLI RAUT
| 10th Jun, 2013,
07:29: PM
Expert Answer:
x2+7x+12
= x2+4x+3x+12
= x(x+4)+3(x+4)
= (x+4)(x+3)
Zeroes are -4 and -3.
Sum of zeroes = -4-3 = -7 = - coefficient of x/ coefficient of x2
Product of zeroes = (-4)(-3) = 12 = constant term/ coefficient of x2
Hence, the relationship between zeroes and the coefficients of the given polynomial is verified.
Answered by
| 10th Jun, 2013,
10:04: PM
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