find value of a and b if 7+^5/7-^5 - 7-^5/7+^5= a+7^5b/11

Asked by harishkumqr312 | 3rd Jan, 2021, 07:37: PM

Expert Answer:

To find the value of a and b if 7+root5/7-root5 - 7-root5/7+root5 = a + (7 root5/11) b
 
fraction numerator 7 plus square root of 5 over denominator 7 minus square root of 5 end fraction minus fraction numerator 7 minus square root of 5 over denominator 7 plus square root of 5 end fraction equals straight a plus fraction numerator 7 square root of 5 over denominator 11 end fraction straight b
rightwards double arrow fraction numerator 49 plus 5 plus 14 square root of 5 minus open parentheses 49 plus 5 minus 14 square root of 5 close parentheses over denominator 49 minus 5 end fraction equals straight a plus fraction numerator 7 square root of 5 over denominator 11 end fraction straight b
rightwards double arrow fraction numerator 28 square root of 5 over denominator 44 end fraction equals straight a plus fraction numerator 7 square root of 5 over denominator 11 end fraction straight b
rightwards double arrow fraction numerator 7 square root of 5 over denominator 11 end fraction equals straight a plus fraction numerator 7 square root of 5 over denominator 11 end fraction straight b
rightwards double arrow straight a equals 0 space space and space straight b equals 1

Answered by Renu Varma | 5th Jan, 2021, 11:11: AM