Find three terms in AP such that their sum is 3 and product is -8.

Asked by Topperlearning User | 20th Nov, 2013, 12:20: AM

Expert Answer:

Let a - d, a and a + d be three terms in AP.

According to the question,

a - d + a + a + d = 3

3a = 3 or a = 1

(a - d) (a) (a + d) = -8

a(a2 - d2) = -8

Putting the value of a = 1, we get,

1 - d2 = -8

d2 = 9 or d = ±3

Thus, the required three terms are -2, 1, 4 or 4,1,-2.

Answered by  | 20th Nov, 2013, 02:20: AM