Find three consecutive terms in A.P whose sum is 9 and the product of their cubes is 3375 

Asked by pushpa.Kudle09 | 12th Mar, 2020, 12:37: AM

Expert Answer:

Let the consecutive terms of an A.P. be a - d, a, a + d 
a - d + a + a + d = 9
3a = 9
a = 3
 
Also
(a - d)3 + a3 + (a + d)3 = 3375
Solving this we get the value of d and then terms after putting a = 3

Answered by Sneha shidid | 12th Mar, 2020, 10:15: AM