CBSE Class 10 Answered
find three consecutive integers whose product is equal to sixteen times its sum.
Asked by deepita0 | 19 May, 2009, 11:11: PM
Expert Answer
Let the three consecutive integers be x, x+1 and x+2. According to the question,
x(x+1)(x+2) = 16 (x+(x+1)+(x+2))
x(x+1)(x+2) = 16 (3x+3)
x(x+1)(x+2) = 16 x 3 (x+1)
x2 + 2x - 48 = 0
x2 + 8x - 6x - 48 = 0
x (x+8) -6 (x+8) = 0
(x-6) (x+8) = 0
x =6 or x= -8
So the numbers are 6, 7,8 or -8,-7,-6
Answered by | 20 May, 2009, 02:31: PM
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