find the zeroes of: g(x)=a(x^2+1)-x(a^2+1)

Asked by sonali garg | 22nd Jun, 2013, 08:25: PM

Expert Answer:

g(x) = a(x^2+1)-x(a^2+1) = ax^2+a-xa^2-x = (a-x)+ax(x-a)=(x-a)(ax-1)
Thus, the zeroes of g(x) are a and 1/a.

Answered by  | 23rd Jun, 2013, 12:44: AM

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