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Find the zeroes of following equation Root 3x2-8x+4root3

Asked by apporv1999 | 24 Jul, 2014, 04:56: PM
answered-by-expert Expert Answer
G i v e n space e q u a t i o n space i s space 3 x squared minus 8 x plus 4 square root of 3 Z e r o s space o f space t h e space e q u a t i o n space i s space g i v e n space b y space fraction numerator minus b plus-or-minus square root of b squared minus 4 a c end root over denominator 2 a end fraction equals fraction numerator 8 plus-or-minus square root of 64 minus 48 square root of 3 end root over denominator 6 end fraction equals fraction numerator 8 plus-or-minus square root of 64 minus 48 square root of 3 end root over denominator 6 end fraction equals fraction numerator 8 plus-or-minus 4 square root of 4 minus 3 square root of 3 end root over denominator 6 end fraction equals fraction numerator 4 plus-or-minus 2 square root of 4 minus 4 square root of 3 end root over denominator 3 end fraction s o space Z e r o s space o f space t h e space g i v e n space e q u a t i o n space a r e space fraction numerator 4 plus 2 square root of 4 minus 4 square root of 3 end root over denominator 3 end fraction comma fraction numerator 4 minus 2 square root of 4 minus 4 square root of 3 end root over denominator 3 end fraction
Answered by Dharma Teja | 25 Jul, 2014, 10:17: AM

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