CBSE Class 10 Answered
find the values of k,for which the quadratic equation has equal roots:kx(x-2)+6(k-2)
Asked by | 09 Jun, 2008, 04:23: PM
Expert Answer
kx(x-2)+6(k-2)
= kx2 - 2kx + 6(k-2)
a = k , b = -2k , c = 6(k-2)
If the discriminant b2 - 4ac equals zero, the radical in the quadratic formula becomes zero.
b2 - 4ac = (-2k)2 - 4.k.6(k-2)
= 4k2 - 24k2 + 48k
= -20k2 + 48k = 0
-5k2 + 12k = 0
-k (5k -12) = 0
k = 0, 12/5
Answered by | 09 Jun, 2008, 05:00: PM
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