find the values of a and b so that the polynomial (x4 + ax2 - 7x2 + 8x + b) is exactly divisible by (x + 2) as well as (x + 3). how to solve this ??
Asked by | 26th Jun, 2011, 12:00: AM
Let f(x) = x4 + ax3 - 7x2 + 8x + b
It is given that f(x) is exactly divisible by (x+2). So the remainder is f(-2) which is equal to 0.
Also, it is given that f(x) is exactly divisible by (x+3). So the remainder is f(-3) which is equal to 0.
Therefore, we have:
f(-2) = 16 - 8a - 28 - 16 + b = 0 or -8a + b - 28 = 0 ... (1)
f(-3) = 81 - 27a - 63 - 24 + b = 0 or -27a + b - 6 = 0 ... (2)
Subtracting (1) from (2),
-19a + 22 = 0
a = 22/19
Now, substitute this value of a in any of the equations (1) or (2) to get the value of b.
Answered by | 26th Jun, 2011, 02:43: PM
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