find the value of x

Asked by  | 20th Feb, 2009, 05:24: PM

Expert Answer:

these two vectors are parallel.

so cross product will be zero.

(2i + 3j - k ) x ( 4i+6j +xk) = 0

12k -2xj -12k +3xi -4j +6i =0

setting coefficients of i and j and k equal to zero.

2x+4 =0  and 3x + 6 =0

==> x= -2

Answered by  | 20th Feb, 2009, 10:48: PM

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