find the value of x
Asked by | 20th Feb, 2009, 05:24: PM
these two vectors are parallel.
so cross product will be zero.
(2i + 3j - k ) x ( 4i+6j +xk) = 0
12k -2xj -12k +3xi -4j +6i =0
setting coefficients of i and j and k equal to zero.
2x+4 =0 and 3x + 6 =0
==> x= -2
Answered by | 20th Feb, 2009, 10:48: PM
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