CBSE Class 11-science Answered
find the value of : sin(n+1)x.sin(n+2)x+cos(n+1)x.cos(n+2)x
Asked by | 02 Mar, 2013, 09:54: AM
Expert Answer
Since sinA.sinB + cosA.cosB = cos (A-B)
so, here sin(n+1)x.sin(n+2)x+cos(n+1)x.cos(n+2)x = cos ( (n+2)x - (n+1)x )
= cos(x)
Answered by | 02 Mar, 2013, 10:01: AM
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