find the value of k if the quadratic polynomial x2+8x+k has zeroes whoose difference is 2 ?
Asked by paritosh mahajan
| 8th Jun, 2013,
04:16: PM
Expert Answer:
Let the zeros of quadratic polynomial be a and b
So, a+b = -8 (Sum of roots of a quadratic equation is equal to -8 (-b/a))
Also, its given that a-b = 2
Hence solving the above 2 equations
2a = -6
a = -3 and b = -5
Now k = product of roots
Hence, k = -5*-3
k = 15
Answered by
| 8th Jun, 2013,
06:49: PM
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