find the value of k if the quadratic polynomial x2+8x+k has zeroes whoose difference is 2 ?

Asked by paritosh mahajan | 8th Jun, 2013, 04:16: PM

Expert Answer:

Let the zeros of quadratic polynomial be a and b
So, a+b = -8 (Sum of roots of  a quadratic equation is equal to -8 (-b/a))
Also, its given that a-b = 2 
Hence solving the above 2 equations 
2a = -6
a = -3 and b = -5
 
Now k = product of roots
Hence, k = -5*-3
k = 15

Answered by  | 8th Jun, 2013, 06:49: PM

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