Find the value of k for which the roots of this equation are real and equal k^2 x^2 - 2(2k-1)x + 4= 0 

Asked by Ashutosh | 21st Feb, 2018, 07:51: PM

Expert Answer:

begin mathsize 16px style straight k squared straight x squared minus 2 open parentheses 2 straight k minus 1 close parentheses straight x plus 4 equals 0
According space to space the space question
straight D equals 0
open square brackets negative 2 open parentheses 2 straight k minus 1 close parentheses close square brackets squared minus 4 straight k squared cross times 4 equals 0
4 open parentheses 4 straight k squared minus 4 straight k plus 1 close parentheses minus 16 straight k squared equals 0
16 straight k squared minus 16 straight k plus 4 minus 16 straight k squared equals 0
minus 16 straight k plus 4 equals 0
16 straight k equals 4
straight k equals 1 fourth end style

Answered by Sneha shidid | 22nd Feb, 2018, 09:33: AM