Find the value of k for which the roots of this equation are real and equal k^2 x^2 - 2(2k-1)x + 4= 0
Asked by Ashutosh | 21st Feb, 2018, 07:51: PM
Answered by Sneha shidid | 22nd Feb, 2018, 09:33: AM
- (4-k)x^2 + (2k+4)x + (8k+1) = 0
- factorise 7x^2-9x+2
- For what value of k , (4-k)x2 +(2k+4)x +(8k+1) = 0 is a perfect square
- Prove that both the roots of the equation (x-a)(x-b)=m^2 are always real.
- for what value of 'k' will the following quadratic equation: (k+1)x2-4kx+9=0 have real and equal roots? Solve the equation.
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number