Find the value of g such that line x-2/9=x-1/g=z+3/-6 is perpendicular to the plane 3x-y-2z=7

Asked by Aarushi - | 9th Feb, 2012, 11:49: AM

Expert Answer:

If the line is pependicular to the plane then , the line and the normal vector to the plane must be parallel
that is , 3/9 = -1/g = -2/-6
g = -3

Answered by  | 9th Feb, 2012, 02:48: PM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.