CBSE Class 10 Answered
Find the value of
cos42 + cos78 + cos162
Asked by Ayesha Maria Zahir | 21 Jul, 2013, 11:58: AM
Expert Answer
cos42o + cos78o + cos162o
= cos42o + cos78o + cos(180o - 18o)
= cos42o + cos78o - cos18o
= 2cos[(42o + 78o)/2] cos[(78o - 42o)/2] - cos18o
= 2cos60o cos18o - cos18o
= cos18o - cos18o = 0
Answered by | 21 Jul, 2013, 06:19: PM
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