find the unit vector perpendicular to the plane ABC

Asked by  | 20th Feb, 2009, 05:35: PM

Expert Answer:

AB =vevtor of B - vector of A = (1-3 , -1-(-1) , -3-2 ) = (-2,0,-5)    similarly AC = (1,-2,-1)

now find out AB  AC =  (-10i - 7j + 4k)

and unit vector  = (-10i - 7j + 4k) /  (100+49+16) =  (-10i - 7j + 4k) /  165

Answered by  | 22nd Feb, 2009, 12:41: PM

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