find the unit vector perpendicular to the plane ABC
Asked by | 20th Feb, 2009, 05:35: PM
Expert Answer:
AB =vevtor of B - vector of A = (1-3 , -1-(-1) , -3-2 ) = (-2,0,-5) similarly AC = (1,-2,-1)
now find out AB 
AC = (-10i - 7j + 4k)
and unit vector = (-10i - 7j + 4k) / 
(100+49+16) = (-10i - 7j + 4k) / 165
Answered by | 22nd Feb, 2009, 12:41: PM
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