fIND THE UNIT VECTOR PERPENDICULAR TO EACH OF THE VECTORS: 3i+j+2k AND 2i-2j+4k.
Asked by devanshu_jain | 14th Oct, 2010, 01:47: PM
A vector perpendicular to both of the given vectors can be found out by finding the cross product of the two vectors.
A = (3i+j+2k) x (2i-2j+4k.) = 8i -8j -8k
unit vector = A / |A| = (8i -8j -8k) / √(82+82+82) = (i-j-k)/√3.
Answered by | 15th Oct, 2010, 12:14: AM
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