Find the total charge and the charge stored between the plates of each capacitor.
Asked by Topperlearning User | 22nd Apr, 2015, 11:11: AM
Clearly, the capacitors are in parallel.
Therefore, Ctot = C1 + C2 = 4 mF + 6 mF = 10 mF
Charge on C1 = 4 x 10-6 F × 20 V = 8.0 × 10-5 C = 80 mC.
Charge on C2 = 6 × 10-6 F × 20 V = 12.0 × 10-5 C = 120 mC.
Total charge = 80 mC + 120 mC = 200 mC.
Answered by | 22nd Apr, 2015, 01:11: PM
- Sir For how much marks it can be asked
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