Find the total charge and the charge stored between the plates of each capacitor.

Asked by Topperlearning User | 22nd Apr, 2015, 11:11: AM

Expert Answer:

Clearly, the capacitors are in parallel.                                                                      

Therefore, Ctot = C1 + C2 = 4 mF + 6 mF = 10 mF                                                    

 Charge on C1 = 4 x 10-6 F × 20 V = 8.0 × 10-5 C = 80 mC.                                                       

Charge on C2 = 6 × 10-6 F × 20 V = 12.0 × 10-5 C = 120 mC. 

Total charge = 80 mC + 120 mC = 200 mC.

Answered by  | 22nd Apr, 2015, 01:11: PM