CBSE Class 10 Answered
first divide 30 by 7 = 4 and remainder 2. therefore 31 is the first term for the progression { we want the R=3}
to find the last term divide 300 by 7 , we will get 42 and R = 6 . therefore 297 which is the last term { when divided by 7 leaves 3 as R }
now we know the first term and the last term as 31 and 297 with common difference 7
the sequence will be 31,38,45,..... 297
to calculate the no . of terms ... the last term Tn = 31 + ( n - 1 ) . 7 = 297
( n-1) . 7 = 297 - 31 = 266
( n - 1 ) 266 / 7 = 38====> n = 38 +1 ==39
the sum of the integers === 31 + 38 + 45 + ...............297(( 39 terms))
S 39 = 39 / 2 ( 31 + 297 ) ==> 39 / 2 ( 328 ) = 39 x 164 =6396
sum of integers between 30 and 300 when divided by 7 leaves 3 as R == 6396