Find the sum of n terms of the series (4-1/n)+(4-2/n)+(4-3/n)+.....

Asked by raginisood35 | 1st Jun, 2020, 08:24: PM

Expert Answer:

(4-1/n)+(4-2/n)+(4-3/n)+.....+(4-n/n)
= (4+4+...+upto n terms) - 1/n(1+2+3+...+n)
= 4n - 1/n[n(n+1)/2]
= 4n - (n+1)/2
= (8n - n - 1)/2
= (7n-1)/2

Answered by Renu Varma | 2nd Jun, 2020, 11:36: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.