CBSE Class 10 Answered
find the sum of all two-digit natural numbers which when divided by 4 yields 2 as remainder.
Asked by deepitapai | 26 Jan, 2009, 08:08: AM
Expert Answer
The first such natural number is 6.Note that all such numbers will have a gap of 4 between them.
So the numbers are 6,10,14..
the last two digit number is 98
So sum of all these numbers is the sum of A.P.
6+10+14+...98
This A.P. clearly has 24 terms.
So, use the formula for sum of n terms of an A.P. with first term=a=6
common difference =d=4
number of terms =n=24
So you can get the answer using the formula for sum of n terms
={n/2}{2a+(n-1)d}
Answered by | 26 Jan, 2009, 01:03: PM
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