find the sum of all three digit numbers which when divided by 16 leaves remainder 6?

Asked by  | 13th Jun, 2008, 07:17: PM

Expert Answer:

the first term = 102  ,  which divided by 16 leaves  remainder6

 the second term = 118 ....... last term == 998

 to calculate  the no . term,,    998  =   102  + ( n-1) 16

                                                                  102 + 16n - 16   ======>  n = 57

 the sum of all terms =   57 / 2 [ 2 (102)  +  ( 57-1)  16 ]

                                              57 / 2 [ 204  + 56 (16) ]

                                             = 31350

 

 

Answered by  | 26th Jul, 2008, 04:36: PM

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