CBSE Class 10 Answered
find the sum of all three digit numbers which when divided by 16 leaves remainder 6?
Asked by | 13 Jun, 2008, 07:17: PM
Expert Answer
the first term = 102 , which divided by 16 leaves remainder6
the second term = 118 ....... last term == 998
to calculate the no . term,, 998 = 102 + ( n-1) 16
102 + 16n - 16 ======> n = 57
the sum of all terms = 57 / 2 [ 2 (102) + ( 57-1) 16 ]
57 / 2 [ 204 + 56 (16) ]
= 31350
Answered by | 26 Jul, 2008, 04:36: PM
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