Find the sum of all three digit number which when divided by 16 leaves remainder 7?
Asked by | 9th Jun, 2008, 01:12: PM
The first such 3 digit number is 103 and the last such number is 999.
The terms in between form an AP with a common difference of 16.
Find the number of terms, n using the relation 999 = 103+16(n-1)
Find the sum using the relation Sn = n/2[a+l]
Answered by | 24th Jun, 2008, 05:42: PM
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