Find the sum of all three digit number which when divided by 16 leaves remainder 7?

Asked by  | 9th Jun, 2008, 01:12: PM

Expert Answer:

The first such 3 digit number is 103 and the last such number is 999.

The terms in between form an AP with a common difference of 16.

Find the number of terms, n using the relation 999 = 103+16(n-1)

Find the sum using the relation Sn = n/2[a+l]

Answered by  | 24th Jun, 2008, 05:42: PM

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