Find the sum of all three digit number which when divided by 16 leaves remainder 6?

Asked by  | 1st Jun, 2008, 01:53: PM

Expert Answer:

So the sequence is 118,134 ,..........998
There are altogether = 62-7=55numbers   so n=55   ,a1=118 and an=998
Therefore sum of this sequence is = n/2(a1+an) = 55/2(118+998)=55 x 555 = 30525

Answered by  | 25th Jul, 2008, 05:37: PM

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