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Find the sum of all three digit number which when divided by 16 leaves remainder 6?
Asked by | 01 Jun, 2008, 01:53: PM Expert Answer
So the sequence is 118,134 ,..........998
There are altogether = 62-7=55numbers   so n=55   ,a1=118 and an=998
Therefore sum of this sequence is = n/2(a1+an) = 55/2(118+998)=55 x 555 = 30525
Answered by | 25 Jul, 2008, 05:37: PM
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