CBSE Class 10 Answered
3 digit numbers = 100 , 101 ..... 999
3 digit numbers which divided by 4 leaves 1 as remainder are 101, 105, 109, ....................997
the total number of terms = = Tn = 101 + { n-1} 4 == 997
101 +4n - 4 = 997
97 +4n == 997
4n = 900
===> 900 / 4 = 225
the sum of 225 terms = Sn = 225/ 2 { 2 (101) +( 225-1) 4 ]
225 [ / 2 [ 202+896] ==> 123525