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ICSE Class 8 Answered

Find the smallest number which 69120 e must be divided to obtain a perfect cube also find the cube root of that perfect cube
Asked by kamrankhan2013jsr | 11 Sep, 2020, 06:54: AM
Expert Answer

Prime Factorisation of 69120 = 2 × 2 × 2 × × 2 × 2 × × 2 × 2 × × 3 × 3 × 5

To make 69120 a perfect cube, it shoulb be divided by 5.

69120 ÷ 5 = 13824

Prime Factorisation of 13824 = 2 × 2 × 2 × × 2 × 2 × × 2 × 2 × × 3 × 3 

Cube root of 13824 = 2 × 2 × 2 × 3 =24

Answered by Yasmeen Khan | 11 Sep, 2020, 09:57: AM
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