find the smallest no.when no.30,40,and 60,divided and leaves remainder 7
Asked by singhaarzoo155 | 16th May, 2021, 07:38: PM
Q: Find the smallest number which when divided by 30, 40 and 60 leaves remainder 7 in each case.
The LCM of 30, 40 and 60 is 120.
So, 120 when divided by 30, 40 and 60, leaves remainder 0.
Adding 7, we get 127
When 127 divided by 30, 40 and 60, leaves remainder 7 in each case.
Hence, the required number is 127.
Answered by Renu Varma | 17th May, 2021, 10:56: AM
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