CBSE Class 10 Answered
Find the roots of the equation
1/2x-3 + 1/x-5 = 1
Asked by | 27 Oct, 2012, 09:07: AM
Expert Answer
Answer : to find the roots of given equation :
[1/(2x-3) ] + [1/ (x-5)] = 1
=> x-5+2x-3 = (2x-3)(x-5) {taking the LCM and multiplying the denomenator on RHS}
=> 2x2-16x+23 = 0
it is a quadratic equation where a = 2 , b =-16 , c = 23
D = b2 - 4ac
= (-16)2 - 4 (2)(23)
= 256 - 184
= 72
= k2 + 16
x = (-b + D1/2 ) / 2a and x = (-b - D1/2 ) / 2a
=> x = (16 + 721/2) / 4 and (16 - 721/2) / 4
=> x = [16 + 6 (21/2) ] /4 and [16 - 6 (21/2) ] /4
=> x = [8 + 3 (21/2) ] /2 and [8 - 3 (21/2) ] /2 Answer
Answered by | 27 Oct, 2012, 07:12: PM
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