find the relative molecular mass of a gas 0.546g of which occupies 360cm3 at 87 degree cen. and 380mm Hg pressure.(1 litre of hydrogen at STP weighs0.09g
Asked by SUNITA | 22nd Jul, 2013, 12:29: PM
Expert Answer:
P1 = 380 mm P2 = 760mm
P1V1/T1 = P2V2/T2
V1= 360 cc V2 = X cc
so, V2 = P1V1T2/T1P2 = 380 x 360 x 273/360 x 760 = 136.5 cc
T1 = 87 +273 K
T2 = 273 K
So, 136.5 cc of the gas at STP weighs = 0.546 g
Therefore, 1000 cc of the gas at STP weighs = 0.564/136.5 x 1000 = 4 g
We know Vapour density = wt of 1000 ml gas/wt of 1000 ml of H2 = 4/0.09 = 44.44
Relative molecular mass or mw of gas = 2 x VD = 2 x 44.44 = 88.88 g
P1 = 380 mm P2 = 760mm
P1V1/T1 = P2V2/T2
V1= 360 cc V2 = X cc
so, V2 = P1V1T2/T1P2 = 380 x 360 x 273/360 x 760 = 136.5 cc
T1 = 87 +273 K
T2 = 273 K
So, 136.5 cc of the gas at STP weighs = 0.546 g
Therefore, 1000 cc of the gas at STP weighs = 0.564/136.5 x 1000 = 4 g
We know Vapour density = wt of 1000 ml gas/wt of 1000 ml of H2 = 4/0.09 = 44.44
Relative molecular mass or mw of gas = 2 x VD = 2 x 44.44 = 88.88 g
Answered by | 23rd Jul, 2013, 10:21: AM
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