Find the ratio in which the line 3x+y-9=0 divides the line segment joining the points A(1,3), B(2,7).
Asked by sandra j maria | 21st Jan, 2014, 07:53: PM
Let the point (x,y) divides AB in the ratio k:1.
By section formula,
x = (2k+1)/(k+1) , y = (7k+3)/(k+1)
Now, this point also lies on the given line so it would satisfy the equation 3x+y-9=0
3(2k+1) + (7k+3) -9(k+1) = 0
k = 3/4
Hence, the required ratio is 3:4.
Answered by | 21st Jan, 2014, 11:08: PM
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