find the point on y axis which is equidistant from the points (5,-2) and (-3,2)

Asked by  | 31st Jan, 2012, 07:59: PM

Expert Answer:

Let P(0,y) be the required point. Let A (5, -2), B (-3, 2) be the given points. Then PA^2 = PB^2 (0-5)^2 + (y+2)^2= (0+3)^2 + (y-2)^2 On solving, we get, y=-2. Thus, the required point is (0, -2).

Answered by  | 31st Jan, 2012, 09:34: PM

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