Find the point on x-axis which is equidistant from the points (-2,5) and (2,-3).

### Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Let the point on x-axis be (a,0)

Since
PA = PB _{} PA^{2}
= PB^{2}

_{} (a + 2)^{2} + (0 - 5)^{2} =
(a - 2)^{2} + (0 + 3)^{2}

_{} (a + 2)^{2} - (a - 2)^{2} =
9 - 25 = -16

_{} 8a = -16 _{} a = -2.

_{} The required point is (-2,0).

### Answered by | 4th Jun, 2014, 03:23: PM

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