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CBSE Class 10 Answered

Find the point on x-axis which is equidistant from the points (-2,5) and (2,-3).
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

Let the point on x-axis be (a,0)

Since PA = PB PA2 = PB2

(a + 2)2 + (0 - 5)2 = (a - 2)2 + (0 + 3)2

(a + 2)2 - (a - 2)2 = 9 - 25 = -16

8a = -16 a = -2.

The required point is (-2,0).

Answered by | 04 Jun, 2014, 03:23: PM

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