Find the point on x-axis which is equidistant from the points (-2,5) and (2,-3).

Asked by Topperlearning User | 4th Jun, 2014, 01:23: PM

Expert Answer:

Let the point on x-axis be (a,0)

Since PA = PB PA2 = PB2

(a + 2)2 + (0 - 5)2 = (a - 2)2 + (0 + 3)2

(a + 2)2 - (a - 2)2 = 9 - 25 = -16

8a = -16 a = -2.

The required point is (-2,0).

Answered by  | 4th Jun, 2014, 03:23: PM