Find the ordinate of a point who use abscissa is 10and which is at a distance of 10 units from the point P(2,-3).

Asked by saif abbas | 31st Oct, 2010, 02:45: PM

Expert Answer:

Dear Student,
Let the ordinate of the point be y, then the point is (10, y).
Using distance formula,
D = [(x2 - x1)2 + (y2 - y1)2]1/2
D2 = [(x2 - x1)2 + (y2 - y1)2]
102 = (10 - 2)2 + (y - (-3))2
100 = 64 + (y + 3)2
 (y + 3)2 = 36
y + 3 = ±6
y = 3 or -9
regards,
Team,
TopperLearning.

Answered by  | 31st Oct, 2010, 10:24: PM

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