Find the ordinate of a point who use abscissa is 10and which is at a distance of 10 units from the point P(2,-3).

Dear Student,

Let the ordinate of the point be y, then the point is (10, y).

Using distance formula,

D = [(x₂ - x₁)² + (y₂ - y₁)²]^1/2

D² = [(x₂ - x₁)² + (y₂ - y₁)²]

10² = (10 - 2)² + (y - (-3))²

100 = 64 + (y + 3)²

 (y + 3)² = 36

y + 3 = ±6

y = 3 or -9

regards,

Team,

TopperLearning.