CBSE Class 11-science Answered

The word AGAIN has 5 letters in which A is repeated 2 times.

_{Therefore, the required number of possible words}

_{While arranging these words in the dictionary, the words beginning with A will come first.}

_{For this, fixing the first letter as A, we arrange the remaining 4 letters taken all at a time. Note that all the remaining 4 letters are different.}

_{So, the number of words starting with A is 4! = 24.}

_{Next fixing G in the first position, we have 4 remaining letters in which 2 are of one kind.}

_{Then, starting with G, the number of words}

_{Similarly, fixing letter I in the first place, the number of words so obtained are 12.}

_{Total number of words so far obtained = 24 + 12 + 12 = 48.}

_{The next word would definitely begin with letter N.}

_{The 49th word is NAAGI and the 50th word is NAAIG.}