Find the number of integral zeros of x2-6x+12

Asked by janasati | 15th Jul, 2009, 06:41: PM

Expert Answer:

x2 -6x + 12

D = 62  - 4Χ1X12=36-48=-12<0

Therefore, equation will not have any real root but two complex  or imaginary  roots

Answered by  | 16th Jul, 2009, 09:01: AM

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