Find the number of integral zeros of x2-6x+12
Asked by janasati | 15th Jul, 2009, 06:41: PM
Expert Answer:
x2 -6x + 12
D = 62 - 4Χ1X12=36-48=-12<0
Therefore, equation will not have any real root but two complex or imaginary roots
Answered by | 16th Jul, 2009, 09:01: AM
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